<?php $image_path="http://fc04.deviantart.net/fs71/f/2010/227/4/6/PNG_Test_by_Destron23.png"; echo exif_imagetype($image_path);?>
It returned 3
because png
response type as maciej said.
Try this to get like this image/png
:
echo mime_content_type($image_path);
Try this:
$finfo = finfo_open(FILEINFO_MIME_TYPE); // return mime type ala mimetype extension echo finfo_file($finfo, $image_path) . "\n";finfo_close($finfo);